Asked by Isaber

For what real number k does the product (25 + ki)(3+2i) equal a real number?


I tried dividing by i. So I got: ((25/i)+k)((3/i+2) which would equal (-25i+k)*(-3i+2)
which means k would=25i. I don't think that's right but can you guys check it?
Answered by Scott
when you FOIL the binomials, the i terms have to cancel

(25 * 2i) + (3 * ki) = 0
Answered by Isaber
Thank you!
Answered by meow
meow
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