Asked by Alyssa
A box is on a flat plane and has a force of 16 N applied downward to it at an angle of 55 degrees. The box has a mass of 28 kg.
What is the minimum horizontal force F needed to make the box start moving in (Figure 1)? The coefficients of kinetic and static friction between the box and the floor are 0.25 and 0.41, respectively.
What is the minimum horizontal force F needed to make the box start moving in (Figure 1)? The coefficients of kinetic and static friction between the box and the floor are 0.25 and 0.41, respectively.
Answers
Answered by
Henry
Fap = 16N[55o], Downward.
M*g = 28*9.8 = 274.4 N. = Wt. of box.
Fn = Mg + Fap*Sin55 = 274.4 + 16*sin55 = 287.5 N.
Fs = u*Fn = 0.41 * 287.5 = 117.9 N. = Force of static friction.
F+Fap*Cos55-Fs = M*a.
F+16*Cos55-117.9 = 28*0
F + 9.18 - 117.9 = 0
F = 108.7 N.
M*g = 28*9.8 = 274.4 N. = Wt. of box.
Fn = Mg + Fap*Sin55 = 274.4 + 16*sin55 = 287.5 N.
Fs = u*Fn = 0.41 * 287.5 = 117.9 N. = Force of static friction.
F+Fap*Cos55-Fs = M*a.
F+16*Cos55-117.9 = 28*0
F + 9.18 - 117.9 = 0
F = 108.7 N.
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