Asked by Ella
An estimate for negative square root of 93 is ___
A-8.1
B-8.5
C-9.1**
D-9.5
Julie is digging a square area in her backyard for a vegetable garden. If the area is 52 square feet, what is the approximate length of one side of her garden?
A:6FT**
B:7FT
C:8FT
D:9FT
Please correct me if I'm wrong.
A-8.1
B-8.5
C-9.1**
D-9.5
Julie is digging a square area in her backyard for a vegetable garden. If the area is 52 square feet, what is the approximate length of one side of her garden?
A:6FT**
B:7FT
C:8FT
D:9FT
Please correct me if I'm wrong.
Answers
Answered by
Anonymous
An estimate for negative square root of 93 is ____.
[-(sqrt(93))] If its an imaginary just apply absolute value
Find perfect squares close to 93.
9^2 = 81
10^2 = 100
Find the difference between the squares and 93. (The smaller the value the closer it is to the root of the square.)
100 - 93 = 7
93 - 81 = 12
So, the first answer is D.) -9.5
Test taking strategy: Use the answer options and square them.
9.1 * 9.1 ~= 82
9.5 * 9.5 ~= 90
[-(sqrt(93))] If its an imaginary just apply absolute value
Find perfect squares close to 93.
9^2 = 81
10^2 = 100
Find the difference between the squares and 93. (The smaller the value the closer it is to the root of the square.)
100 - 93 = 7
93 - 81 = 12
So, the first answer is D.) -9.5
Test taking strategy: Use the answer options and square them.
9.1 * 9.1 ~= 82
9.5 * 9.5 ~= 90
Answered by
Anonymous
Julie is digging a square area in her backyard for a vegetable garden. If the area is 52 square feet, what is the approximate length of one side of her garden?
A Square's Area is the length of one side multiplied by itself. This problem has the same approach given for the first question.
Find perfect squares close to 52.
7^2 = 7*7 = 49
8^2 = 8*8 = 64
Find the differences. (Smaller is better)(Make sure the differences are positive numbers.)
53 - 49 = 4
64 - 53 = 11
So 7FT is closer.
A Square's Area is the length of one side multiplied by itself. This problem has the same approach given for the first question.
Find perfect squares close to 52.
7^2 = 7*7 = 49
8^2 = 8*8 = 64
Find the differences. (Smaller is better)(Make sure the differences are positive numbers.)
53 - 49 = 4
64 - 53 = 11
So 7FT is closer.
Answered by
Anonymous
Here is a table for x^2.
SQUARES
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^8 = 64
9^2 = 81
SQUARES
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^8 = 64
9^2 = 81
Answered by
Sly
1. C
2. B
3. D
4. B
2. B
3. D
4. B
Answered by
Loveeeeee
Thank you sly!! 100%
Answered by
BleakTuber
Sly is correct!!!
Answered by
kjgy
Sly is correct!!!
Answered by
paullon
the answer
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