Asked by abhilash

if tanB=3/4
then show that
3sin2B + 4cos2B =4
Answered by Steve
tanB = 3/4
sinB = 3/5
cosB = 4/5
(Draw a 3-4-5 right triangle to see this)

Now recall your double-angle formulas:
sin2B = 2 sinB cosB
cos2B = cos^2B - sin^2B

Now just plug in your numbers...
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