Question
The sides of a rectangular floor are 5 and (x+5).the diagonal is x+8.calculate in metres.the area of the floor
Answers
Steve
to find x, solve
5^2 + (x+5)^2 = (x+8)^2
25+x^2+10x+25 = x^2+16x+64
6x+14 = 0
x = -7/3
So, the area is (5)(5-7/3) = 5*8/3 = 13 1/3 m^2
5^2 + (x+5)^2 = (x+8)^2
25+x^2+10x+25 = x^2+16x+64
6x+14 = 0
x = -7/3
So, the area is (5)(5-7/3) = 5*8/3 = 13 1/3 m^2