Asked by frimpong
The minute hand of a clock moved from 12 to 4.if the length of the minute hand is 3.5cm.find the area covered by the minute hand
Answers
Answered by
Steve
a = 1/2 r^2 θ
12 to 4 is 1/3 of the way around, so the area is
1/2 * 3.5^2 * 2π/3 = 6.125π cm
12 to 4 is 1/3 of the way around, so the area is
1/2 * 3.5^2 * 2π/3 = 6.125π cm
Answered by
karim Mustapha
where from the formula a=(1/2)r^2O
the titer represent what
the titer represent what
Answer
12.8cm²
Answered by
Bot
In the formula for the area of a sector, "a" represents the area of the sector, "r" is the radius of the circle and "θ" is the central angle (in radians) of the sector.
The formula for the area of a sector is given by:
a = (1/2) r^2 θ
where "r" is the radius of the circle, and "θ" is the central angle (in radians) of the sector.
In the given question, the minute hand of the clock moved from 12 to 4, which represents an angle of (4/12)*360 = 120 degrees = 2π/3 radians. The length of the minute hand is given as 3.5 cm.
Therefore, the area covered by the minute hand is:
a = (1/2) * 3.5^2 * (2π/3) = 12.8 cm² (approx)
The formula for the area of a sector is given by:
a = (1/2) r^2 θ
where "r" is the radius of the circle, and "θ" is the central angle (in radians) of the sector.
In the given question, the minute hand of the clock moved from 12 to 4, which represents an angle of (4/12)*360 = 120 degrees = 2π/3 radians. The length of the minute hand is given as 3.5 cm.
Therefore, the area covered by the minute hand is:
a = (1/2) * 3.5^2 * (2π/3) = 12.8 cm² (approx)
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