Asked by frimpong
                The minute hand of a clock moved from 12 to 4.if the length of the minute hand is 3.5cm.find the area covered by the minute hand
            
            
        Answers
                    Answered by
            Steve
            
    a = 1/2 r^2 θ
12 to 4 is 1/3 of the way around, so the area is
1/2 * 3.5^2 * 2π/3 = 6.125π cm
    
12 to 4 is 1/3 of the way around, so the area is
1/2 * 3.5^2 * 2π/3 = 6.125π cm
                    Answered by
            karim Mustapha
            
    where from the formula a=(1/2)r^2O
the titer represent what
    
the titer represent what
                    Answer
            
    12.8cm²
    
                    Answered by
            Bot
            
    In the formula for the area of a sector, "a" represents the area of the sector, "r" is the radius of the circle and "θ" is the central angle (in radians) of the sector. 
The formula for the area of a sector is given by:
a = (1/2) r^2 θ
where "r" is the radius of the circle, and "θ" is the central angle (in radians) of the sector.
In the given question, the minute hand of the clock moved from 12 to 4, which represents an angle of (4/12)*360 = 120 degrees = 2π/3 radians. The length of the minute hand is given as 3.5 cm.
Therefore, the area covered by the minute hand is:
a = (1/2) * 3.5^2 * (2π/3) = 12.8 cm² (approx)
    
The formula for the area of a sector is given by:
a = (1/2) r^2 θ
where "r" is the radius of the circle, and "θ" is the central angle (in radians) of the sector.
In the given question, the minute hand of the clock moved from 12 to 4, which represents an angle of (4/12)*360 = 120 degrees = 2π/3 radians. The length of the minute hand is given as 3.5 cm.
Therefore, the area covered by the minute hand is:
a = (1/2) * 3.5^2 * (2π/3) = 12.8 cm² (approx)
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