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When the following reaction reaches equilibrium, the concentrations are 2.26 M A, 0.50 M B, and 2.00 M C. Calculate the equilibrium constant.

A+2B<=====>3C
Answered by Pakistan
Kc=0.884 with no unit
Answered by shamara
A+2B<=====>3c
Kc=[c]3/[A][b]2
Kc=[2.00]3 /[2.26][0.5]2
Kc=8.365/[2.26][0.25]
Kc=8.365/0.565
Kc=14.8
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