Asked by Anonymous
A Lamborghini sports car can accelerate from zero to 60 mph in 4 seconds. It can decelerate from 60 mph to rest in 120 ft. What is the ratio of average acceleration over average deceleration? (1 mile = 5280 ft).
I know the answer is .682, but I'm not sure how to get to that.
I know the answer is .682, but I'm not sure how to get to that.
Answers
Answered by
Anonymous
How do you know the answer is .682 if you can't get there.
Answered by
Henry
V = 60mi/h * 1600m/mi * 1h/3600s = 26.7 m/s.
V = Vo + a*t = 26.7.
0 + a*4 = 26.7
a = 6.67 m/s^2.
d = 120Ft/(3.3ft/m) = 36.4 m.
V^2 = Vo^2 + 2a*d = 0.
(26.7)^2 + 2a*36.4 = 0
a = -9.79 m/s^2.
deceleration = 9.79 m/s^2.
Ratio = 6.67/9.79 = 0.681.
V = Vo + a*t = 26.7.
0 + a*4 = 26.7
a = 6.67 m/s^2.
d = 120Ft/(3.3ft/m) = 36.4 m.
V^2 = Vo^2 + 2a*d = 0.
(26.7)^2 + 2a*36.4 = 0
a = -9.79 m/s^2.
deceleration = 9.79 m/s^2.
Ratio = 6.67/9.79 = 0.681.
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