Question
The following questions are about the reaction of sodium oxide with nitric acid.
1)What mass of sodium oxide would be needed to react with acid to form 0.5 mol salt?
I said 1.5
2) How much sodium oxide would be required to neutralise 230cm3 of 1.0moldm-3?
3) 2.0gof sodium oxide was DDED TO 230CM3 OF 0.05MOLDM-3 HNO3 solution. Once all the acid has reacted the remaining sodium oxide will react with water to form an alkali.
a)What mass of alkali will be formed?
b)What will the concentration of the alkali solution be?
Please help i'm really confused and tell me please if i got 1 right
1)What mass of sodium oxide would be needed to react with acid to form 0.5 mol salt?
I said 1.5
2) How much sodium oxide would be required to neutralise 230cm3 of 1.0moldm-3?
3) 2.0gof sodium oxide was DDED TO 230CM3 OF 0.05MOLDM-3 HNO3 solution. Once all the acid has reacted the remaining sodium oxide will react with water to form an alkali.
a)What mass of alkali will be formed?
b)What will the concentration of the alkali solution be?
Please help i'm really confused and tell me please if i got 1 right
Answers
is the last one 0.0416
Na2O + 2HNO3 ==> 2NaNO3 + H2O
1. 1.5 what? grams? tons? bushels? I didn't get 1.5 grams.
3.
00416 what? Show your work.
1. 1.5 what? grams? tons? bushels? I didn't get 1.5 grams.
3.
00416 what? Show your work.
Please help im sure i did it all wrong
You may not have done it wrong depending upon what the units were.
Na2O + 2HNO3 ==> 2NaNO3 + H2O
You want 0.5 mol NaNO3; how much Na2O is needed? So
0.5 mol NaNO3 x (1 mols Na2O/2 mol NaNO3) = ? molNa2O.
Then grams Na2O = mols Na2O x molar mass Na2O.
Na2O + 2HNO3 ==> 2NaNO3 + H2O
You want 0.5 mol NaNO3; how much Na2O is needed? So
0.5 mol NaNO3 x (1 mols Na2O/2 mol NaNO3) = ? molNa2O.
Then grams Na2O = mols Na2O x molar mass Na2O.
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