Asked by 0ooooooooo0
The following questions are about the reaction of sodium oxide with nitric acid.
1)What mass of sodium oxide would be needed to react with acid to form 0.5 mol salt?
I said 1.5
2) How much sodium oxide would be required to neutralise 230cm3 of 1.0moldm-3?
3) 2.0gof sodium oxide was DDED TO 230CM3 OF 0.05MOLDM-3 HNO3 solution. Once all the acid has reacted the remaining sodium oxide will react with water to form an alkali.
a)What mass of alkali will be formed?
b)What will the concentration of the alkali solution be?
Please help i'm really confused and tell me please if i got 1 right
1)What mass of sodium oxide would be needed to react with acid to form 0.5 mol salt?
I said 1.5
2) How much sodium oxide would be required to neutralise 230cm3 of 1.0moldm-3?
3) 2.0gof sodium oxide was DDED TO 230CM3 OF 0.05MOLDM-3 HNO3 solution. Once all the acid has reacted the remaining sodium oxide will react with water to form an alkali.
a)What mass of alkali will be formed?
b)What will the concentration of the alkali solution be?
Please help i'm really confused and tell me please if i got 1 right
Answers
Answered by
0ooooooooo0
is the last one 0.0416
Answered by
DrBob222
Na2O + 2HNO3 ==> 2NaNO3 + H2O
1. 1.5 what? grams? tons? bushels? I didn't get 1.5 grams.
3.
00416 what? Show your work.
1. 1.5 what? grams? tons? bushels? I didn't get 1.5 grams.
3.
00416 what? Show your work.
Answered by
0ooooooooo0
Please help im sure i did it all wrong
Answered by
DrBob222
You may not have done it wrong depending upon what the units were.
Na2O + 2HNO3 ==> 2NaNO3 + H2O
You want 0.5 mol NaNO3; how much Na2O is needed? So
0.5 mol NaNO3 x (1 mols Na2O/2 mol NaNO3) = ? molNa2O.
Then grams Na2O = mols Na2O x molar mass Na2O.
Na2O + 2HNO3 ==> 2NaNO3 + H2O
You want 0.5 mol NaNO3; how much Na2O is needed? So
0.5 mol NaNO3 x (1 mols Na2O/2 mol NaNO3) = ? molNa2O.
Then grams Na2O = mols Na2O x molar mass Na2O.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.