Asked by Anonymous
A plane heads south at 320 mph and the wind is west at 80 m/s. What is the final speed and angle degree of the plane?
Answers
Answered by
Henry
X = -80m/s * 3600s/h * (1/1600)mi/m =
-180mi/h.
Y = ver. = -320mi/h.
tanA = Y/X = -320 / -180 = 1.778,
Ar = 60.64 deg. Ar = Reference angle.
A=Ar + 180 = 60.64 + 180 = 240.64 deg.
R = X / cosA = -180 / cos240.64 = 367mi/h @ 240.64 deg.
-180mi/h.
Y = ver. = -320mi/h.
tanA = Y/X = -320 / -180 = 1.778,
Ar = 60.64 deg. Ar = Reference angle.
A=Ar + 180 = 60.64 + 180 = 240.64 deg.
R = X / cosA = -180 / cos240.64 = 367mi/h @ 240.64 deg.
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