Question
1.25 grams of an acidnis completely neutralised by 25ml of a 0.25M Ba(OH)2 SOLUTION.which of the following statements are correct.
a)if the acid is dibasic its molar mass would be 200
b)if it is dibasic /0.5g of the acid would neutralise completely 12.5ml of 0.40N NaOH.
C)volume of base used is independent of strength of the acid
a)if the acid is dibasic its molar mass would be 200
b)if it is dibasic /0.5g of the acid would neutralise completely 12.5ml of 0.40N NaOH.
C)volume of base used is independent of strength of the acid
Answers
The only way I know to do this is to work each answer as a separate problem.
a. H2A + Ba(OH)2 ==> BaA + 2H2O
mols Ba(OH)2 = M x L = ?
mols = grams/molar mass. You have mols from above and grams from the problem, solve for molar mass. If you get 200 for molar mass then a must be right.
b. mols H2A = grams/molar mass. Use 0.5 g as in the problem and use molar mass found in part a. Then
H2A + 2NaOH ==> Na2A + 2H2O
Convert mols H2A to mols NaOH needed and compare with mols generated by 12.5 mL of 0.40M NaOH. YOu do that with mols = M x L = ? This answer will tell you if b is correct or not.
c. C is a dumb answer; you know it can't be right.
a. H2A + Ba(OH)2 ==> BaA + 2H2O
mols Ba(OH)2 = M x L = ?
mols = grams/molar mass. You have mols from above and grams from the problem, solve for molar mass. If you get 200 for molar mass then a must be right.
b. mols H2A = grams/molar mass. Use 0.5 g as in the problem and use molar mass found in part a. Then
H2A + 2NaOH ==> Na2A + 2H2O
Convert mols H2A to mols NaOH needed and compare with mols generated by 12.5 mL of 0.40M NaOH. YOu do that with mols = M x L = ? This answer will tell you if b is correct or not.
c. C is a dumb answer; you know it can't be right.
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