Question

An airplane traveling at 200 mph in a direction of 40 degrees north of east encounters a wind blowing east at 50.0 mph. Find the velocity of the plane measured from the ground.
240.5 mph @ E32.3°N
V = 200[40o] + 50[0o].
V = 200*Cos40+200*sin40 + 50
V = 153.2+128.6i + 50 = 203.2 + 128.6i = 240.5mi/h[32.3o] N. of E.



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