Asked by shadow
find the length of the hypotenuse of a triangle with legs of 5 ft and 12 ft?
11 ft
13 ft
17 ft
60 ft
11 ft
13 ft
17 ft
60 ft
Answers
Answered by
Scott
it's one of the "Pythagorean triples"
right triangles with integer sides
like 3-4-5
remember ... a^2 + b^2 = c^2
right triangles with integer sides
like 3-4-5
remember ... a^2 + b^2 = c^2
Answered by
Steve
there are a few basic integer-sided right triangles you would do well to learn. These start with
3-4-5
5-12-13
8-15-17
7-24-25
and all multiples of these, such as
6-8-10, 10-40-50, ...
However, to solve the problem in general, the hypotenuse is
c^2 = a^2+b^2
In your case, we have
c^2 = 5^2 + 12^2 = 25+144 = 169 = 13^2
so, c = 13
3-4-5
5-12-13
8-15-17
7-24-25
and all multiples of these, such as
6-8-10, 10-40-50, ...
However, to solve the problem in general, the hypotenuse is
c^2 = a^2+b^2
In your case, we have
c^2 = 5^2 + 12^2 = 25+144 = 169 = 13^2
so, c = 13
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