Asked by Ajun
A professor gave his 40 students a test with three questions. Every student answered at least one question. Ten didn't answer the first question. 14 didn't answer the second question. 12 didn't answer the third question. If 18 students answered all three questions, how many answered exactly one question?
Thanks for your help
Thanks for your help
Answers
Answered by
Scott
t = two answers , x = one answer
(3 * 40) - (3 * 18) - 10 - 14 - 12 = 2 t + x
40 - 18 = t + x
solve the system for x
(3 * 40) - (3 * 18) - 10 - 14 - 12 = 2 t + x
40 - 18 = t + x
solve the system for x
Answered by
MathMate
Another way to solve.
Let
A=# of students who answered the first question
B=# of students who answered the second question
C=# of students who answered the third question
Then
we are given
B+C-|B∩C| = 10
A+C-|A∩C| = 14
A+B-|A∩B| = 12
Add three equations
2A+2B+2C-(|A∩B|+|B∩C|+|C∩A|)=36....(1)
But the total number who answered one OR two question is 40-18=22, or
A+B+C-|A∩B|- |B∩C|-|C∩A|=22.....(2)
(1)-(2)
A+B+C=36-22=14
Let
A=# of students who answered the first question
B=# of students who answered the second question
C=# of students who answered the third question
Then
we are given
B+C-|B∩C| = 10
A+C-|A∩C| = 14
A+B-|A∩B| = 12
Add three equations
2A+2B+2C-(|A∩B|+|B∩C|+|C∩A|)=36....(1)
But the total number who answered one OR two question is 40-18=22, or
A+B+C-|A∩B|- |B∩C|-|C∩A|=22.....(2)
(1)-(2)
A+B+C=36-22=14
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