Asked by Angel
I m doing an assignment and this is what is asks: (c) Find the sum of the squares of the cosines of the corresponding coordinate direction angles found above. (Measure the cosines of the corresponding coordinate direction angles from the x-y plane.)
Im not quite sure what it is asking me to do. Part a and b got me to find angles alpha, beta and gamma for 2 vectors with the same magnitude but different directions.
If someone can explain to me what I should be doing that would be great. If you need the values or some other info let me know.
Thanks
Im not quite sure what it is asking me to do. Part a and b got me to find angles alpha, beta and gamma for 2 vectors with the same magnitude but different directions.
If someone can explain to me what I should be doing that would be great. If you need the values or some other info let me know.
Thanks
Answers
Answered by
Damon
I am sorry, I have no idea what these angles alpha, beta and gamma are for the two vectors. Are they in three dimensions and the angles to the x, y and z axes? In that case the three angles do not define the direction of a vector. The direction depends not only on the angle to the three axes but also the ORDER in which you do the rotations.
Answered by
Damon
I bet it is 2 d
say angle alpha above x axis in xy plane
same vector is angle beta to y axis
call vector length h
then cos alpha = x/h and cos^2 = x^2/h^2
cos beta = y/h and cos^2 = y^2/h^2
sum = (x^2+y^2)/h^2
BUT
h is hypotenuse = sqrt(x^2 + y^2)
so we have h^2/h^2 = 1
perhaps this is what they mean.
say angle alpha above x axis in xy plane
same vector is angle beta to y axis
call vector length h
then cos alpha = x/h and cos^2 = x^2/h^2
cos beta = y/h and cos^2 = y^2/h^2
sum = (x^2+y^2)/h^2
BUT
h is hypotenuse = sqrt(x^2 + y^2)
so we have h^2/h^2 = 1
perhaps this is what they mean.
Answered by
Damon
Of course you could do that much more easily with geometry :)