Asked by Anonymous
Susan invests 3 times as much money at
9% as she does at 6%. If her total interest after 1 year is $1980, how much does she have invested at each rate?
9% as she does at 6%. If her total interest after 1 year is $1980, how much does she have invested at each rate?
Answers
Answered by
Steve
Just write the info in math. If $x is invested at 6%, then
.09*3x + .06x = 1980
.09*3x + .06x = 1980
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