Asked by John
9.3mL of ammonia base cleaner requires 12mL of 1M HCL to reach end point. A) what is molarity of ammonia and b) what is percentage of ammonia
Answers
Answered by
DrBob222
NH3 + HCl ==> NH4Cl
mols HCl = M x L = ?
mols NH3 = the same. Look at the coefficients in the balanced equation.
M NH3 = mols NH3/L NH3 = ?
For percentage is that w/w, w/v, what?
I will assume w/v (weight/volume).
mols NH3 from above x molar mass NH3 = grams NH3.
Then (g NH3/9.3 mL)*100 = % NH3 w/v
mols HCl = M x L = ?
mols NH3 = the same. Look at the coefficients in the balanced equation.
M NH3 = mols NH3/L NH3 = ?
For percentage is that w/w, w/v, what?
I will assume w/v (weight/volume).
mols NH3 from above x molar mass NH3 = grams NH3.
Then (g NH3/9.3 mL)*100 = % NH3 w/v
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