a(n-3)+8=b solve for n

Question

an-3a +8=b (subtracted an from left side) I get:
3a+8 = b-an

=3a +8 = b-a(n)

=3a+8/b-a = n

but i think this is wrong...help...thank you

Answer 1

You are right. It is wrong

an-3a +8=b (subtracted an from left side)
Yes but
I get:
3a+8 = b-an
NO
-3a + 8 = b - an
an - 3a + 8 = b
an = 3a+b-8
n = (3a+b-8)/a

Answer 2

from : an-3a +8=b

an = 3a + b - 8
n = (3a + b - 8)/a

Answer 3

subtract 8 ... a(n-3) = b-8

divide by a ... n - 3 = (b-8)/a

add 3 ... n = [(b-8)/a] + 3