tan3x= radical3 / 3

tan3x=(3tanx-tan^3x)/(1-3tan^2x)

1. If f(x)=tan3x, find f'(x) and f'(3). 2. let f(x)=3cos(cosx), find f'(x). i got stuck. i do...

integrate sec^2(3x)(e^(tan3x))

1=radical3-3p-2p

Prove that tan3x-tan2x-tanx=tan3xtan2xtanx

Find domain of tanx/tan3x

4 radical3 + 2 radical48 in simplest form

tan3x tan2x tanx = tan3x - tan2x-tanx

tan3x tan2x tanx = tan3x - tan2x-tanx proof that

tan3x tan2x tanx = tan3x - tan2x-tanx proof that very easy

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