Asked by Majiri
An object weighs 100N on the earth's surface. Find its weight at a point P with orbital radius 2R. [g =
10NKg-1
10NKg-1
Answers
Answered by
Damon
G = universal gravitational constant
F = G Me m/r^2
G Me and m do not change
so
F' = G Me m /(2r)^2 = G Me m /4r^2
so
100/4
= 25 N
(assuming it has no velocity, like not in orbit :)
F = G Me m/r^2
G Me and m do not change
so
F' = G Me m /(2r)^2 = G Me m /4r^2
so
100/4
= 25 N
(assuming it has no velocity, like not in orbit :)
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