Asked by Caity
In the javelin throw at a track-and-field event, the javelin is launched at a speed of 33.0 m/s at an angle of 36.5° above the horizontal. How much time is required for it to hit the target that is the same height across the field?
Answers
Answered by
Scott
the flight time is ...
2 [(launch velocity)(sine launch angle) / g]
2 [(launch velocity)(sine launch angle) / g]
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