Question
In the javelin throw at a track-and-field event, the javelin is launched at a speed of 33.0 m/s at an angle of 36.5° above the horizontal. How much time is required for it to hit the target that is the same height across the field?
Answers
Scott
the flight time is ...
2 [(launch velocity)(sine launch angle) / g]
2 [(launch velocity)(sine launch angle) / g]