Current flows out of a 110V source through a 10 ohm resistor and then through parallel branches, one containing a 20 ohm resistor and the other a 30 ohm resistor. Find V I R P
V I R P
50 5 10 250
60 3 20 180
60 2 30 120
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110 5 22 550
First R total:
1/R= 1/20 + 1/30
1/R= 1/12
12 + 10= 22 ohms
Now I find current:
I= 110/22
I= 5 A
current same in series so 10 ohm resistor is also 5 A
Voltage:
Now I can find 10 ohm voltage
5 * 10= 50 v
110 -50= 60 v left over for parallel
60 v must be in each parallel because treated as one
now I find I of 20 and 30 ohm resistors:
I=60/20
I=60/30
so 3, and 2 ohm
power is P= IV
Please let me know if my thinking is off.
Thank you
it is correct.
4 answers