You have 3 choices for the first digit
and 3 choices for the middle digit, but
only 2 choices for the last digit
number of possible numbers = (3)(3)(2) = 18
How many ODD three digit numbers is it possible to make using the numbers 4, 5 and 7 if you are allowed to use each of the numbers more than once in a particular three digit number?
2 answers
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