Question
How do I find a and b given the equation ax^2 + bx -4 and a vertex point of (1,-6)?
Answers
Scott
the vertex is on the axis of symmetry
x = -b / 2a ... 2a = - b
plugging the point into the main equation
... -6 = a(1^2) + b(1) - 4
... -2 = a + b
use the two equations to find a and b
x = -b / 2a ... 2a = - b
plugging the point into the main equation
... -6 = a(1^2) + b(1) - 4
... -2 = a + b
use the two equations to find a and b