n+3P6 : n+2P4 = 14 : 1. Find 'n' .

Answer 1

n+3P6 = (n+3)(n+2)(n+1)(n)(n-1)(n-2)
n+2P4 = (n+2)(n+1)(n)(n-1)

(n+3)(n-2) = 14
n=4