Question
Find an equation of a line perpendicular to the given line and contains the given point. Write the equation in slope-intercept form.
a. line 3x+y=5, point (-1,2)
b. line y=3x+1, point (6,1)
a. line 3x+y=5, point (-1,2)
b. line y=3x+1, point (6,1)
Answers
Steve
do like the other one, but use the perpendicular slope.
3x+y=5 has slope -3
so, the perpendicular line has slope 1/3
The new line is thus
y-2 = 1/3 (x+1)
now rearrange to slope-intercept form
do the other one in like wise.
3x+y=5 has slope -3
so, the perpendicular line has slope 1/3
The new line is thus
y-2 = 1/3 (x+1)
now rearrange to slope-intercept form
do the other one in like wise.