Asked by diana
this is for proving identies and its fustrating i can't solve this one question! lol
x=feta
(btw the first part is supposed to be divided by the bottom)
1 + 2sinxcosx + sinxcosx
sinx + cosx
(1 + 2sinxcosx / sinx + cosx) + sinxcosx
x=feta
(btw the first part is supposed to be divided by the bottom)
1 + 2sinxcosx + sinxcosx
sinx + cosx
(1 + 2sinxcosx / sinx + cosx) + sinxcosx
Answers
Answered by
diana
oh shoot i wrote it wrong
its:
1 + 2sinxcosx = sinxcosx
sinx + cosx
its:
1 + 2sinxcosx = sinxcosx
sinx + cosx
Answered by
Reiny
I believe you still wrote it wrong.
it should be
(1 + 2sinxcosx)/(sinx + cosx) = sinx + cosx
to prove this, recall that sin^2 x + cos^2 x = 1
so replace the 1 with that.
LS = (sin^2 x + 2sinxcosx + cos^2 x)/(sinx + cosx)
= (sinx + cosx)^2/(sinx + cosx)
= sinx + cosx
= RS
it should be
(1 + 2sinxcosx)/(sinx + cosx) = sinx + cosx
to prove this, recall that sin^2 x + cos^2 x = 1
so replace the 1 with that.
LS = (sin^2 x + 2sinxcosx + cos^2 x)/(sinx + cosx)
= (sinx + cosx)^2/(sinx + cosx)
= sinx + cosx
= RS
Answered by
diana
thank you:)
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