Asked by william

What is the mass of the organic substance formed by heating of 21.0g of butanoate of ammonium, admitting that the reaction presents a yield of 50%?

8 years ago

Answered by DrBob222

CH3CH2CH2COONH4 + heat ==>CH3CH2CH2COOH + NH3
21.0 x (mm product acid/mm reactant) x 0.5 = ?
whee mm stands for molar mass.

8 years ago

Answered by william

thanks

8 years ago

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