Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 25.1 percent of its original value?

asked by chan

7 years ago

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1 answer

ln(100/25.1) = kt
k = 0.693/t_1/2
sUBSTITUTE AND SOLVE FOR t.

answered by DrBob222

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Question

Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 25.1 percent of its original value?

1 answer

ln(100/25.1) = kt
k = 0.693/t_1/2
sUBSTITUTE AND SOLVE FOR t.

DrBob222 · Answer

ln(100/25.1) = kt k = 0.693/t_1/2 sUBSTITUTE AND SOLVE FOR t.