Asked by Anonymous
Graph the inequality on the numberline and then write it in interval notation.
6x+5(x+5)≥7x+45
and
12x+4(x-3)<3x+53
Please help me with these equation and how to write the solution on a numberline. Thanks.
6x+5(x+5)≥7x+45
and
12x+4(x-3)<3x+53
Please help me with these equation and how to write the solution on a numberline. Thanks.
Answers
Answered by
Damon
6x+5(x+5)≥7x+45
11 x + 25 ≥ 7 x + 45
4 x ≥ 20
x ≥ 5
black dot at x = 5, arrow to right
11 x + 25 ≥ 7 x + 45
4 x ≥ 20
x ≥ 5
black dot at x = 5, arrow to right
Answered by
Damon
12 x + 4 x -12 < 3 x + 53
13 x < 65
x < 65/3
open circle at x = 65/3 and arrow to left
13 x < 65
x < 65/3
open circle at x = 65/3 and arrow to left
Answered by
Anonymous
What would the interval notation be for
6x+5(x+5)≥7x+45
x ≥ 5
6x+5(x+5)≥7x+45
x ≥ 5
Answered by
Anonymous
Thank You Damon for the assistance with interval notation and graphing. I am horrible at this section.
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