Asked by Anonymous
If 28.8 grams of calcium carbonate react to form 16.1 grams of calcium oxide, how many grams of carbon dioxide must simultaneously be formed?
Answers
Answered by
Damon
molar Mass CaCO3 = 40+12+48 = 100 g/mol
CaO = 40 + 16 = 56 g/mol
CO2 = 12+32 = 44 g/mol
so
28.8 (44/100) = 12.7 grams
CaO = 40 + 16 = 56 g/mol
CO2 = 12+32 = 44 g/mol
so
28.8 (44/100) = 12.7 grams
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