Asked by Anonymous
                If 28.8 grams of calcium carbonate react to form 16.1 grams of calcium oxide, how many grams of carbon dioxide must simultaneously be formed?
            
            
        Answers
                    Answered by
            Damon
            
    molar Mass CaCO3 = 40+12+48 = 100 g/mol
CaO = 40 + 16 = 56 g/mol
CO2 = 12+32 = 44 g/mol
so
28.8 (44/100) = 12.7 grams
    
CaO = 40 + 16 = 56 g/mol
CO2 = 12+32 = 44 g/mol
so
28.8 (44/100) = 12.7 grams
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