Asked by joseph
a motorbike weighs 400kg accelerates uniformly at 1.5m/s2 from rest to 22m/s. then the brakes are applied and it stops 2.5s later.
(a)Sketch a graph showing the motion history
(b)From the sketch,determine the total distance traveled
(c)Determine the momentum of the car before the break was applied.
(a)Sketch a graph showing the motion history
(b)From the sketch,determine the total distance traveled
(c)Determine the momentum of the car before the break was applied.
Answers
Answered by
bobpursley
a. "weighs" 400kg. I assume has a mass of ...
a) graph should be velocity vs time. Starting at Om/s at t=0 and of a slope of 1.5m/s^2 to it gets to 22 m/s, about at time
22=1.5*t or time= 14 2/3 second
then at that time, v slopes from 22m/s to zero at time 14 2/3 + 2 seconds.
b. distance is the area under the graph
break it into smaller units and count.
c) momentum=400*22m/s
a) graph should be velocity vs time. Starting at Om/s at t=0 and of a slope of 1.5m/s^2 to it gets to 22 m/s, about at time
22=1.5*t or time= 14 2/3 second
then at that time, v slopes from 22m/s to zero at time 14 2/3 + 2 seconds.
b. distance is the area under the graph
break it into smaller units and count.
c) momentum=400*22m/s
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