Asked by Shania
What volume of distilled water should be added to 500ml of a solution of sulphuric acid to 90% by weight, density 1.81 g.mL-1, to obtain a 10 Molar solution?
Answers
Answered by
Writeacher
snow, Taylor, Shania
Please pick one name and keep it. Playing games with multiple names doesn't get help faster.
Please pick one name and keep it. Playing games with multiple names doesn't get help faster.
Answered by
DrBob222
First determine the M of the initial H2SO4. That's
1.81 g/mL x 1000 mL x 0.90 x 1/98 = ?M which I will call y.
Then mL1 x M1 = mL2 x M2
500 mL x yM = mL2 x 10
Solve for mL2 which is approx 850. Subtract 500 from that to see what volume should be added. The answer is approx 350.
1.81 g/mL x 1000 mL x 0.90 x 1/98 = ?M which I will call y.
Then mL1 x M1 = mL2 x M2
500 mL x yM = mL2 x 10
Solve for mL2 which is approx 850. Subtract 500 from that to see what volume should be added. The answer is approx 350.
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