Asked by Anonymous
Mukul has$1.60 in nickels, dimes, and quarters. He has nine more dimes than quarters and six more nickels than quarters. How many of each coin are in his pocket.
d=# dimes
n=# nickels
q= # quarters
d+n+q=1.60
d+9=q
n+6=q
0.1d+0.05n+0.25q=1.60
d=# dimes
n=# nickels
q= # quarters
d+n+q=1.60
d+9=q
n+6=q
0.1d+0.05n+0.25q=1.60
Answers
Answered by
Scott
10 d + 5 n + 25 q = 160
d = q + 9
n = q + 6
substituting
... 10(q + 9) + 5(q + 6) + 25 q = 160
solve for q,
then substitute back to find d and n
d = q + 9
n = q + 6
substituting
... 10(q + 9) + 5(q + 6) + 25 q = 160
solve for q,
then substitute back to find d and n
Answered by
Anonymous
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