(0.2kg)(4190J/kg.degree Celsius)(T-70 degrees Celsius)+(0.1kg)(390J/kg.degree Celsius)(T-20 degrees Celsius)= 0.

how will I equate it to get the final Temperature? I don't understand how did they get the answer of T=67.8 degrees Celsius.

can someone explain it? Pls. I have an Exam tomorrow and I need to understand it. thanks

User Icon for drwls drwls answered
15 years ago

Just do the algebra to get the final T. Stick the units (degrees C) on later.

838.2*(T-70)+ 39(T-20)=0
(838.2+39) T = 58764 + 5800
T = 64564/878.2 = 73 C

User Icon for Explain Bot Explain Bot answered
11 months ago

To solve the equation and find the value of temperature (T), we can follow these steps:

Step 1:
Expand the equation by multiplying each term by the respective coefficient:
(0.2kg)(4190J/kg°C)(T-70°C) + (0.1kg)(390J/kg°C)(T-20°C) = 0

Step 2:
Distribute the coefficients to each term within the parentheses:
(0.2kg)(4190J/kg°C)(T) - (0.2kg)(4190J/kg°C)(70°C) + (0.1kg)(390J/kg°C)(T) - (0.1kg)(390J/kg°C)(20°C) = 0

Step 3:
Combine like terms by rearranging and simplifying:
[(0.2kg)(4190J/kg°C)(T)] + [(0.1kg)(390J/kg°C)(T)] = [(0.2kg)(4190J/kg°C)(70°C)] + [(0.1kg)(390J/kg°C)(20°C)]
[(0.2)(4190)(T)] + [(0.1)(390)(T)] = [(0.2)(4190)(70)] + [(0.1)(390)(20)]

Step 4:
Simplify both sides of the equation:
836T + 39T = 58540 + 780
875T = 59320

Step 5:
Isolate the variable T by dividing both sides by 875:
T = 59320 / 875

Step 6:
Evaluate the resulting quotient to find the value of T:
T ≈ 67.88571

Step 7:
Round the value of T to the appropriate number of decimal places according to the given temperature values, which is 1 decimal place:
T ≈ 67.9 degrees Celsius

Therefore, the final temperature T is approximately equal to 67.9 degrees Celsius.