Asked by Thousif
Three objects A, B, C are at vertices P, Q and R respectively of square PQRS of side 1km speed of these objects are 36km/hr 10m/s 0.8km/min initially they are at rest and start moving in clockwise direction simultaneously
1)which of the objects have the maximum speed?
A. B. C. SAME SPED?
2)By what time A reaches vertex Q distance between the objects B and C is -----kms
3/4. 4/3. 5/6. 6/5
3)Time after A will meet B is
1min20sec. 1min. 1min30sec. 1min40sec
4) Time after which all of them are at starting position is?
1min. 18min. 20min. 30min
1)which of the objects have the maximum speed?
A. B. C. SAME SPED?
2)By what time A reaches vertex Q distance between the objects B and C is -----kms
3/4. 4/3. 5/6. 6/5
3)Time after A will meet B is
1min20sec. 1min. 1min30sec. 1min40sec
4) Time after which all of them are at starting position is?
1min. 18min. 20min. 30min
Answers
Answered by
Steve
For comparison, change all to m/s:
36 km/hr = 36000m/3600s = 10 m/s
.8km/min = 800m/60s = 13.33 m/s
A takes 100 seconds to reach Q.
By that time,
B has reached R
C has passed S and is 33.33 m toward P
So, BC = √(1000^2 + 33.33^2) meters
Since A and B are both moving at 10 m/s, A will never catch B.
C is moving 4/3 as fast as A and B. It will travel 4 times around PQRS while they go 3 laps. So, all will be back home after 300 seconds.
Check my math and check for typos, since #3 has no solution.
36 km/hr = 36000m/3600s = 10 m/s
.8km/min = 800m/60s = 13.33 m/s
A takes 100 seconds to reach Q.
By that time,
B has reached R
C has passed S and is 33.33 m toward P
So, BC = √(1000^2 + 33.33^2) meters
Since A and B are both moving at 10 m/s, A will never catch B.
C is moving 4/3 as fast as A and B. It will travel 4 times around PQRS while they go 3 laps. So, all will be back home after 300 seconds.
Check my math and check for typos, since #3 has no solution.
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