Write a pythagorean triplet whose smallest number is 6

Answer 1

so you want
6^2 + b^2 = c^2
b^2 = c^2 - 36

clearly c > 6, so try values of c so when 36 is subtracted from c^2 you are left with a perfect square.
e.g. let c = 7
is 49 - 36 a perfect square ??? nope!
so try c = 8 , etc
should not take you long to find it

Answer 2

what is the sum of first n odd natural number