Asked by Anonymous
Billy is framing a picture with a rectangular frame. The frame has a perimeter of 62 inches. The height of the frame is 2⁄3 times the length. Find the dimensions of the rectangle.
a. Define the variable(s)
b. Write an equation to represent the situation.
c. Solve.
im stuck on how to start this
a. Define the variable(s)
b. Write an equation to represent the situation.
c. Solve.
im stuck on how to start this
Answers
Answered by
Damon
2 h + 2 L = 62
so
L = 31 - h
h = 2 L/3
so
L = 1.5 h
1.5 h = 31 - h
2.5 h = 31
h = 12.4
L = 18.6
so
L = 31 - h
h = 2 L/3
so
L = 1.5 h
1.5 h = 31 - h
2.5 h = 31
h = 12.4
L = 18.6
Answered by
Anonymous
i understand most of this, but I'm a bit confused on this part:
h = 2L/3
so
L = 31 - h
how did you get this?
h = 2L/3
so
L = 31 - h
how did you get this?
Answered by
Damon
if 2 L + 2 h = 62 given
then L + h = 31
and L = 31 - h
if h = 2L/3 given
then L = 3 h/2 = 1.5 h
then L + h = 31
and L = 31 - h
if h = 2L/3 given
then L = 3 h/2 = 1.5 h
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