Question
Billy is framing a picture with a rectangular frame. The frame has a perimeter of 62 inches. The height of the frame is 2⁄3 times the length. Find the dimensions of the rectangle.
a. Define the variable(s)
b. Write an equation to represent the situation.
c. Solve.
im stuck on how to start this
a. Define the variable(s)
b. Write an equation to represent the situation.
c. Solve.
im stuck on how to start this
Answers
2 h + 2 L = 62
so
L = 31 - h
h = 2 L/3
so
L = 1.5 h
1.5 h = 31 - h
2.5 h = 31
h = 12.4
L = 18.6
so
L = 31 - h
h = 2 L/3
so
L = 1.5 h
1.5 h = 31 - h
2.5 h = 31
h = 12.4
L = 18.6
i understand most of this, but I'm a bit confused on this part:
h = 2L/3
so
L = 31 - h
how did you get this?
h = 2L/3
so
L = 31 - h
how did you get this?
if 2 L + 2 h = 62 given
then L + h = 31
and L = 31 - h
if h = 2L/3 given
then L = 3 h/2 = 1.5 h
then L + h = 31
and L = 31 - h
if h = 2L/3 given
then L = 3 h/2 = 1.5 h
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