Asked by Tayb
Find a unit vector that is parallel to the line tangent to the parabola y = x^2 at the point (4, 16).
Answers
Answered by
Steve
the slope at (4,16) is 8.
So, the tangent vector is
i + 8j
The unit vector is just that, divided by the length: √65
So, the tangent vector is
i + 8j
The unit vector is just that, divided by the length: √65
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.