And what is the experiment? What is the reaction? Is this it?
CuSO4.5H2O + 4NH3 --> [Cu(NH3)4]SO4.5H2O
mols CuSO4.5H2O = grams/molar mass = ?
mols NH3 = M x L = ?
Now convert mols each to mols product using the coefficients in the balanced equation. It's done this way.
mols product = mols CuSO4.5H2O x (1 mol product/1 mol CuSO4.5H2O) = ?
mols product = mols NH3 x (1 mol product/4 mols NH3) = ?
The smaller number is the amount of product formed and the reagent responsible for that is the limiting reagent.
What is the limiting reactant in this experiment? Assume you used 1.0 g of the copper(II) sulfate pentahydrate and 7. 5 mL of 6.0 M NH3. Show your calculations.
Its been a while need some help, thanks!
1 answer