Asked by Anonymous
What is the freezing-point depression of water in a solution of 100g of sucrose, C12 H22 O11, and 500g of water? (Molar freezing point depression constant for water is -1.86°C/m.)
Answers
Answered by
bobpursley
molality= molesSucrose/kgwater
= 100/(342*.5)=.58
deltaTf= m*(-1.86)=-1.09C
= 100/(342*.5)=.58
deltaTf= m*(-1.86)=-1.09C
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.