Asked by kumar
Of three numbers, second is twice the first and is also thrice the third. If the average of three numbers is 44, find the largest.
Answers
Answered by
Steve
If the three numbers are x,y,z, then we know that
y = 2x
y = 3z
(x+y+z)/3 = 44
Now just find z.
y = 2x
y = 3z
(x+y+z)/3 = 44
Now just find z.
Answered by
kumar
pl explain how can we find z. what is the answer.
Answered by
Steve
clear the fraction, and you have
x+y+z = 3*44 = 132
Now, since y=2x=3z,
2x=3z, and x = 3z/2
Now just add them up and you have
3z/2 + 3z + z = 132
11z/2 = 132
z = 132 * 2/11 = 24
x+y+z = 3*44 = 132
Now, since y=2x=3z,
2x=3z, and x = 3z/2
Now just add them up and you have
3z/2 + 3z + z = 132
11z/2 = 132
z = 132 * 2/11 = 24
Answered by
kumar
Thank u sir.
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