Question
A solid body weights 5N in water and 7N in Oil of relative density 0.85.The relative density of solid body material is?
Answers
Anonymous
1.375
dp
how is it possible explination plz
Srinivas Gowda P
Ta = 5N
TB = 7N
Ta/TB = Ss-Sa/Ss-Sb
5/7= Ss-1/Ss-0.85
5Ss-4.25 = 7Ss-7
Ss=1.375
Where, Ss: Specific density of solid body
Sa: Specific density of water
SB: Specific density of oil
Ta: Apparent weight of body in water
TB : Apparent weight of the body in oil
TB = 7N
Ta/TB = Ss-Sa/Ss-Sb
5/7= Ss-1/Ss-0.85
5Ss-4.25 = 7Ss-7
Ss=1.375
Where, Ss: Specific density of solid body
Sa: Specific density of water
SB: Specific density of oil
Ta: Apparent weight of body in water
TB : Apparent weight of the body in oil