Asked by Ann
                When a group of 50 consecutive multiples of 7 is added the answer is 12 075. 
i) What is the smallest of these numbers?
ii) What is the largest of these numbers?
            
            
        i) What is the smallest of these numbers?
ii) What is the largest of these numbers?
Answers
                    Answered by
            Steve
            
    You have a sum of an arithmetic progression, where the common difference is 7.
50/2 (2a+49*7) = 12075
a = 70
70+49*7 = 413
So, numbers range from 70 to 413
    
50/2 (2a+49*7) = 12075
a = 70
70+49*7 = 413
So, numbers range from 70 to 413
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