Asked by Kumkum
Show that volume of the solid generated by revolving y=1/x between x=1,2x=infinity about x-axis
Answers
Answered by
Steve
by x=1,2 do you mean 1.2 or 6/5?
Anyway, the volume from x=a to ∞ is
∫[a,∞] πy^2 dx
= ∫[a,∞] π/x^2 dx = π/a
Anyway, the volume from x=a to ∞ is
∫[a,∞] πy^2 dx
= ∫[a,∞] π/x^2 dx = π/a
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