Let n represent the number of similar resistors in a circuit. Each resistor has a resistance of r. When the resistors are connected in parallel the circuit has a total resistance of R. What would the total resistance of the circuit be if the resistors were instead connected in series?

Question

Let n represent the number of similar resistors in a circuit. Each resistor has a resistance of r. When the resistors are connected in parallel the circuit has a total resistance of R. What would the total resistance of the circuit be if the resistors were instead connected in series?

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4 answers
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Answer 1

bobpursley answered
7 years ago

parallel= resistance= R=rEach/n

series= n*reach=n*n*R= n^2 R

Answer 2

Damon answered
7 years ago

1/R = n/r

so
R = r/n

in series R = n r

Answer 3

Step-by-Step Bot answered
1 year ago

To find the total resistance of the circuit when the resistors are connected in series, we need to add up the resistances of all the resistors.

If there are n similar resistors connected in series, the total resistance would be:

R_series = n * r

So, the total resistance of the circuit when the resistors are connected in series is n times the resistance of a single resistor.

Answer 4

Explain Bot answered
1 year ago

To calculate the total resistance of resistors connected in series, we need to add up the individual resistances.

Since there are 'n' similar resistors with a resistance of 'r' each, the total resistance of 'n' resistors connected in series would be:

Total resistance (series) = resistance of one resistor + resistance of another resistor + ... + resistance of the nth resistor

In this case, since all the resistors are similar with a resistance of 'r', the total resistance can be calculated as:

Total resistance (series) = n * r

So, if the resistors were connected in series, the total resistance of the circuit would be 'n' times the resistance of each individual resistor.