since sum(logs) = log(product) you have
log(2*2^3/7^4) = log 16/2401
log2+3log2-4log7
2 answers
log ( 2 * 2 ^ 3 / 7 ^ 4 ) =
log ( 2 ^ 4 / 7 ^ 4 ) =
log [ ( 2 / 7 ) ^ 4 ] =
4 ∙ [ log ( 2 ) - log ( 7 ) ] =
4 ∙ ( 0.69314718056 - 1.945910149 ) =
4 ∙ ( - 1.25276296845 ) =
- 5.01105187398
OR
log ( 2 * 2 ^ 3 / 7 ^ 4 ) =
log ( 2 * 8 / 2401 ) =
log ( 16 / 2401 ) =
log ( 16 ) - log ( 2401 ) =
2.77258872224 - 7.78364059622 =
- 5.01105187398
In this case:
log is the natural logarithm
log ( 2 ^ 4 / 7 ^ 4 ) =
log [ ( 2 / 7 ) ^ 4 ] =
4 ∙ [ log ( 2 ) - log ( 7 ) ] =
4 ∙ ( 0.69314718056 - 1.945910149 ) =
4 ∙ ( - 1.25276296845 ) =
- 5.01105187398
OR
log ( 2 * 2 ^ 3 / 7 ^ 4 ) =
log ( 2 * 8 / 2401 ) =
log ( 16 / 2401 ) =
log ( 16 ) - log ( 2401 ) =
2.77258872224 - 7.78364059622 =
- 5.01105187398
In this case:
log is the natural logarithm
1 answer