16^x=x^2

2 answers

x=log_16(x^2)
x=2*log_16(x)
1/2=1/x*log_16(x)
1/2=log_16(x^(1/x))
16^(1/2)=x^(1/x)
4=x^(1/x)

no real solution
actually if you just graph them and find the intersection point you get -0.5,
but for the simplified algebraic method, there is no real solution