To find the total surface area of the figure, we need to add up the surface area of each individual section.
Surface area of a circle = πr^2 where r is the radius.
1. Surface area of the first 16 mm section = π(8)^2 = 64π mm^2
2. Surface area of the next 6 mm section = π(3)^2 = 9π mm^2
3. Surface area of the next 10 mm section = π(5)^2 = 25π mm^2
4. Surface area of the next 2 mm section = π(1)^2 = π mm^2
5. Surface area of the next 6 mm section = π(3)^2 = 9π mm^2
6. Surface area of the last 8 mm section = π(4)^2 = 16π mm^2
Adding up all the surface areas:
64π + 9π + 25π + π + 9π + 16π = 124π + 25 mm^2
Therefore, the total surface area of the figure is 124π + 25 mm^2 (approximately) or approximately 394.6 mm^2.
16 mm
6 mm
10 mm
2 mm
6 mm
8 mm
What is the total surface area of the figure?
___mm2
1 answer