16. If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball?

F= ma

a
388.9 m/s2

b
0.003 m/s2

c
315 m/s2

d
3.15 m/s2

e
2.6 m/s2

f
0.32 m/s2

17. If a dolphin swims at 1.85 m/s, how far will the dolphin have traveled after 6.0 s?

a
11 m
b
9.0 m
c
31 m
d
3.2 m

18. What is the gravitational force of attraction between a planet and a 17-kilogram mass that is freely falling toward the surface of the planet at 8.8 m/s2?

a
8.8 N
b
1.9 N
c
150 N
d
0.52 N

19. What type of nuclear radiation is given off in the nuclear reaction below?
35/16 S - ____ +35/17 CI

a
Alpha radiation

b
Gamma radiation

c
Beta radiation

20. A radioisotope has a half-life of 7.5 hours. How many half lives have occured after 67.5 hours?

a
7 half-lives
b
8 half-lives
c
9 half-lives
d
10 half-lives

1 answer

Let's go through your questions one by one:

Question 16: Acceleration of the soccer ball To find the acceleration \( a \), we can use Newton's second law: \[ F = m \cdot a \] Where:

  • \( F = 0.90 , \text{N} \) (force)
  • \( m = 0.350 , \text{kg} \) (mass)

Rearranging the formula to find acceleration: \[ a = \frac{F}{m} = \frac{0.90 , \text{N}}{0.350 , \text{kg}} \approx 2.57 , \text{m/s}^2 \]

Thus, the correct answer is: e. 2.6 m/s² (rounded).


Question 17: Distance traveled by the dolphin To calculate the distance traveled, we can use the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Where:

  • Speed = \( 1.85 , \text{m/s} \)
  • Time = \( 6.0 , \text{s} \)

Calculating: \[ \text{Distance} = 1.85 , \text{m/s} \times 6.0 , \text{s} = 11.1 , \text{m} \]

The closest answer is: a. 11 m.


Question 18: Gravitational force of attraction To find the gravitational force, we can use: \[ F = m \cdot g \] Where:

  • \( m = 17 , \text{kg} \) (mass)
  • \( g = 8.8 , \text{m/s}^2 \) (acceleration due to gravity)

Calculating: \[ F = 17 , \text{kg} \times 8.8 , \text{m/s}^2 = 149.6 , \text{N} \]

Rounding gives approximately: c. 150 N.


Question 19: Type of nuclear radiation Given the reaction: \[ \frac{35}{16} \text{S} \rightarrow \text{?} + \frac{35}{17} \text{Cl} \] This indicates that a beta particle (an electron) is emitted, which increases the atomic number by 1 while keeping the mass number the same.

So, the type of radiation is: c. Beta radiation.


Question 20: Number of half-lives To calculate how many half-lives have occurred in 67.5 hours with a half-life of 7.5 hours: \[ \text{Number of half-lives} = \frac{\text{Total time}}{\text{Half-life}} = \frac{67.5 , \text{hours}}{7.5 , \text{hours}} = 9 \]

Thus, the correct answer is: c. 9 half-lives.


In summary, the answers are: 16. e. 2.6 m/s²
17. a. 11 m
18. c. 150 N
19. c. Beta radiation
20. c. 9 half-lives